Solve the system by the elimination method. Check your work. x-3y=0
3y-6=2x

(-2,-6)
(-6,-1/2)
(-6,-2)

C, (-6,-2)

Step-by-step explanation:

x - 3y = 0 --(1)

3y - 6 = 2x --(2)

We can rearrange equations 1 and 2:

3y - x = 0 --(3)

3y - 2x = 6 --(4)

Subtract 4 from 3:

(3y-3y) + (-2x+x) = (6-0)

-x = 6

x = -6

Substitute x=-2 into any equation. In this case, I substituted it into equation 1 but the value of y would be the same if you substituted it into a different equations:

x - 3y = 0

-6 = 3y

y = -2

Let's check to see if we are right but substituting the values of x and y into both equations

x - 3y = 0

-6 + (-3*-2) = 0

-6 + 6 = 0

0 = 0 Correct

3y - 6 = 2x

3(-2) - 6 = 2(-6)

-6 - 6 = -12

-12 = -12 Correct

Our answer is correct!

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step-by-step explanation:

2/5+1/2=9/10

6/1-9/10=5 1/10

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse