Suppose that 5 j of work is needed to stretch a spring from its natural length of 30 cm to a length of 39 cm.

(a) how much work is needed to stretch the spring from 32 cm to 34 cm? (round your answer to two decimal places.)

(b) how far beyond its natural length will a force of 25 n keep the spring stretched? (round your answer one decimal place.)

Answer

given,

work = 5 J

spring stretch form 30 cm to 39 cm

x = 0.39 - 0.30 = 0.09 m

k = 1234.568 N/m

a) work when spring is stretched from  32 cm to 34 cm

x₂= 0.34 -0.30 = 0.04 m

x₁ = 0.32 - 0.30 = 0.02

W = 0.741 J

b) F = k x

  25 = 1234.568 × x

     x = 0.0205 m

     x = 2.05 cm

in the math equation 8 x 7 = 56, the 8 and the 7 are both factors of 56, since in this lesson we will use square tiles to figure out the factors of a whole find as many different arrays as you can, but follow one important rule: all the rows must have the i can make two rows of nine, so 2 and 9 are both factors of 18.

step-by-step explanation: