Aprojectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) = -16t2 + 704t. after how many seconds does the projectile take to reach its maximum height? show your work.

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22 seconds

Step-by-step explanation:

The maximum height is at the vertex of the parabola.

For a parabola y = ax² + bx + c, the vertex is at x = -b/(2a).

Here, a = -16 and b = 704.

t = -704 / (2 × -16)

t = 22

It takes 22 seconds for the projectile to reach its maximum height.

answer: 12

step-by-step explanation:

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5