If the rms speed of gaseous nitrogen atoms at 300 K is 517 m/s, what is the rms speed of the nitrogen atoms when the gas temperature increases to 600 K?

707 m/s

Explanation:

Since the root mean temperature is directly proportional to the root mean square velocity.

We have

V1/V2 =√T1/T2

V1= root mean square velocity of nitrogen at 300K

V2= root mean square velocity of nitrogen at 600K

Thus;

517/V2 = √300/600

517/V2 = 0.707

V2 = 500/0.707

V2= 707 m/s

wvbbvvv

-4 on