Asample of n2 gas occupied 9.20 l at 21 degrees c and 0.959 atm. if the pressure is tuned to 1.15 atm at constant temperature what is the newly occupied volume

Newly occupied volume is 7.672L by N2 gas.  

Explanation:-

Given  

V= 9.20 L, T(i) = T (f) = 294 K, P (i) = 0.959 atm, P (f) = 1.15 atm

To Find V (f)  

Solution

According to the gas equation  

PV= nRT

Where P=Pressure

V=Volume

n=No of moles

R=Universal gas constant

T=Temperature

Also we know the relation between pressure, volume and temperature as

PV/T = constant

Where P(i)V(i)/T(i) are the initial values of Pressure, Volume and Temperature.

P(f)V(f)/T(f) are the final values of Pressure, Temperature and Volume.

Substitute the known values in the equation we get

=

=

= 7.672 L

Thus the final volume of the system is 7.672 L

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