A fixed 10.8 cm diameter loop of wire is laying in the plane of this paper. A magnetic field of 0.48 T is pointing up, out of the paper. The field is then changed to 0.25 T pointing down into the paper (so the direction of the field is reversed). The time taken to change the magnetic field is 0.16 s. What is the initial magnetic flux through the loop

No bc a lot of things r still theories n unproven

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.