1. A car moving with a velocity of 10 m s-1 accelerates uniformly at 1 m s-2 until it reaches a velocity of 15 m s-1. Calculate (i) the time taken (ii) the distance traveled during the acceleration (ui) the velocity reached 100 m from the place where the acceleration began. m/sec

U ( initial velocity) = 10ms-1
v (final velocity) = 15ms-1
a = 1ms-2

(i)
a = v-u/t

Rearranging the above equation

t = v - u / a

t = 15 - 10 / 1

t = 5 / 1 = 5 s

t = 5s

(ii)

Distance travelled = s = ut + 1/2 at^2

s = 10 * 5 + 1/2 * 1 * 5 * 5

s = 50 + 12.5

s = 62.5m

Umm I don’t really get the last question. Soo can you retype the question in the comment section so that I can answer it.

Anyways, I you have any doubts plz let me know.

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