For an object at distance of 3.00 m, at what distance from the lens is the image formed? the person is farsighted ?

You want this nearsighted person to be able to see very distant objects clearly. That means the spectacle lens must produce an image 30.0 cm from the eye for an object very far away. An image 30.0 cm from the eye will be 28.5 cm to the left of the spectacle lens (see Figure 2). Therefore, we must get di = −28.5 cm when do ≈ ∞. The image distance is negative, because it is on the same side of the spectacle as the object

Explanation:

Since do are known, the power of the spectacle lens can be found using

P

=

1

d

o

+

1

d

i

as written earlier:

P

=

1

d

o

+

1

d

i

=

1

∞

+

1

−

0.285

m

Since

1

∞

=

0

, we obtain:

P

=

0

−

3.51

m

=

−

3.51

D

answer;

d. are made mostly of liquid

explanation;

-the general   composition and structure planets includes; they have a thick gas and liquid layer covering a small,solid core. mostly the gases are hydrogen and helium atmosphere and layers of liquid hydrogen. for instance neptune and uranus are examples of the outer planets, they have a core covered by ice and ammonia.

-neptune's atmosphere is hydrogen and helium with a bit of methane so there is no oxygen to breath and the interior is made up of frozen water and ammonia with a rock and iron core. thus, there is no liquid water or solid surface to survive.