Two forces each of magnitude 25N acts in opposite direction at the opposite end of a circular ring. If the diameter at the ring is 65cm. Calculate the magnitude of the couple acting on the ring​.

The magnitude of the couple is 16.25 Nm.

Explanation:

A couple is a force that always produce a turning effect of objects on which it is applied. It has applications in doors, taps, revolving doors etc. Couple is a two equal but opposite force applied on an object.

couple = force x length

From the given question, the couple acting on the ring can be determined as;

couple = 25 x 0.65

           = 16.25 Nm

The magnitude of the couple is 16.25 Nm.

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west