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a 40 kg-skier starts at the top of a 12-meter high slope. at the bottom, she is traveling 10 m/s. how much energy does she lose to friction? a. she doesn't lose any because mechanical energy is always conserved.
b.4,704 j
c. 2,000 j
d.2,704 j

The initial mechanical energy is the potential energy (PE) which can be solved through the equation,
                             PE = mgh = (40 kg)(9.8 m/s²)(12 m) = 4,704 J 

The energy at the bottom is the kinetic energy and can be calculated through the equation,
                                  KE = 0.5mv² = (0.5)(40 kg)(10 m/s)² = 2000 J
Therefore, she lost 2,704 J of energy due to friction

The center is basically the heart of it