A balloon containing N2 has 1.70 moles and occupies 3.80L. What will the volume be if the number of moles is increased to 2.60moles?
Help me please

5.81L

Explanation:

N1 = 1.70 moles

V1 = 3.80L

V2 = ?

N2 = 2.60 moles

Mole - volume relationship,

N1 / V1 = N2 / V2

V2 = (N2 × V1) / N1

V2 = (2.60 × 3.80) / 1.70

V2 = 9.88 / 1.70

V2 = 5.81 L

The volume of the gas is 5.81L

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