This diagram shows two different forces acting on a skateboarder. The combined mass of the skateboard and the person is 65.2 kg. Based on this
information, what is the acceleration of the skateboarder?

Option C. 0.36 m/s² to the left.

Explanation:

The following data were obtained from the question:

Mass of skateboarder = 65.2 Kg

Force in the right direction (Fᵣ) = 31.8 N

Force in the left direction (Fₗ) = 55.2 N

Acceleration of the skateboarder =.?

Next, we shall determine the net force acting on the skateboarder. This can be obtained as illustrated below:

Force in the right direction (Fᵣ) = 31.8 N

Force in the left direction (Fₗ) = 55.2 N

Net force (Fₙ) =?

Fₙ = Fₗ – Fᵣ

Fₙ = 55.2 – 31.8

Fₙ = 23.4 N to the left

Thus, the net force acting on the skateboarder is 23.4 N to the left.

Finally, we shall determine the acceleration of the skateboarder. This can be obtained as follow:

Mass of skateboarder = 65.2 Kg

Net force (Fₙ) = 23.4 N to the left

Acceleration (a) of the skateboarder =.?

Net force = mass × acceleration

23.4 N = 65.2 × a

Divide both side by 65.2

a = 23.4 / 65.2

a = 0.36 m/s² to the left.

Therefore, the acceleration of the skateboarder is 0.36 m/s² to the left.

C. 0.36 to the left

Explanation:

current and voltage can both be different in different parts of a circuit so it matters where you place the ammeter and voltmete