Solve this system of linear equations. separate the x and y values with a comma 20x=28-8y -8x=-56-8y

20x= 28-8y
-8x=-56-8y

You could solve this by substitution (solving for one variable, x or y, in one equation, then substituting it into the other equation), or elimination. I'll use elimination. In elimination, you can multiple one equation by a value so that, when you add the two equations, one of the variables is cancelled out by the other equation.

(-8x = -56 - 8y) • -1
8x= 56 + 8y

20x = 28 - 8y
+ 8x = 56 + 8y
= 28x = 84 + 0y, or just 28x = 84, since 0 • y = 0.

Divide both sides by 28 to get x alone.

x = 3. Now we have one of our variables. Plug in x=3 to one of the equations to find y. I'll use 20x = 28 - 8y.

20(3) = 28 - 8y

60 = 28 - 8y

Subtract 28 from both sides. You're trying to get y alone.

32 = -8y

Divide both sides by -8.

-4 = y, or y = -4.

The answer is ( 3, -4 ). Hope this helps.

11 mintues is the naswer