An astronaut on the moon drops a feather from rest (v = 0). The acceleration due to gravity is 1.67 m/s 2 . If the feather begins 2 meters above the moon’s surface, what will be its final position after falling for 1.5 seconds?

Given :

Initial velocity , u = 0 m/s .

Acceleration due to gravity on moon , .

Height , h = 2 m .

To Find :

Final position after falling for 1.5 seconds .

Solution :

We know , by equation of motion :

Here , .

So , equation will transform by :

Therefore , the height form moon's surface is 1.88 m .

Hence , this is the required solution .

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