Identify the vertex and the y-intercept of the graph of the function +3 +4

The vertex is at (-3, 4)

This can be found by looking at the basic form of vertex form:

y = (x - h)^2 + k

In this basic form the vertex is (h, k). By looking at what is plugged into the equation, it is clear that h = -3 and k = 4. This means the vertex is at (-3, 4).

The y-intercept is at 13. To find this we must first square the parenthesis and get the equation into standard form.

y = (x + 3)^2 + 4

y = x^2 + 6x + 9 + 4

y = x^2 + 6x + 13

Now we know that the y-intercept is equal to the constant, which is the last number in the equation.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.