launch a rocket ship weighs 4.5 million pounds. When it is launched from rest, it takes 8.00 s to reach 164 km/h ; at the end of the first 1.00 min , its speed is 1640 km/h . Part APart complete What is the average acceleration (in m/s2) of the rocket during the first 8.00 s? aav = 5.69 m/s2 Previous Answers Correct Part BPart complete What is the average acceleration (in m/s2) of the rocket between 8.00 s and the end of the first 1.00 min? aav = 7.88 m/s2 Previous Answers Correct Part CPart complete Assuming the acceleration is constant during each time interval (but not necessarily the same in both intervals), what distance does the rocket travel during the first 8.00 s? Express your answer with the appropriate units. x = 182 m Previous Answers Correct Part D Assuming the acceleration is constant during each time interval (but not necessarily the same in both intervals), what distance does the rocket travel during the interval from 8.00 s to 1.00 min? Express your answer with the appropriate units.

A) a_av = 5.695 m/s²

B) a_av = 7.88 m/s

C) x_f = 182.24 m

D) x_f = 13029.12 m

Explanation:

A) Initial velocity at 0 seconds; v_i = 0 m/s

Final velocity at 8 seconds;v_f = 164 km/h = 45.56 m/s

So, formula for average acceleration is;

a_av = change in velocity/change in time.

Thus, for the first 8 seconds;

a_av = (45.56 - 0)/(8 - 0)

a_av = 45.56/8

a_av = 5.695 m/s²

B) From part A, we now want to find the average acceleration from 8 seconds to 1 minute (60 seconds)

After the 60 seconds, the speed is 1640 km/h = 455.56 m/s

Thus;

Average acceleration is;

a_av = (455.56 - 45.56)/(60 - 8)

a_av = 7.88 m/s

C) Now we are told the acceleration is constant and we want to find the distance the rocket travels during the first 8 seconds.

So, distance formula we will use is;

x_f = x_i + ½(v_i + v_f)t

So at this stage, v_i = 0 m/s and v_f = 45.56 m/s and x_i = 0 m

Thus;

x_f = 0 + ½(0 + 45.56)8

x_f = 182.24 m

D) Now we want to find the distance the rocket travels during the 8 seconds to 1 minute (60 seconds) interval.

From part B, v_i = 45.56 m/s and v_f = 455.56 m/s

Also, x_i = 0 while time interval(t) = 60 - 8 = 52 s

Thus;

x_f = 0 + ½(45.56 + 455.56)52

x_f = 13029.12 m

it may be wrong but i think its a

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day