Plz

avogadro’s law

a rigid container holds 22.4 l of an ideal gas at stp. how many ‘moles’ of gas need to be added to the container to make the pressure equal to 325 kpa?

mol

2.21

Explanation:

At STP, 1 mol of gas has a volume of 22.4 L, so we know we're starting with 1 mol of gas.

Assuming the temperature and volume are held constant, the number of moles needed to reach 325 kPa is found with ideal gas law:

PV = nRT

(325,000 Pa) (0.0224 m³) = n (8.314 Pa m³ / mol / K) (273.15 K)

n = 3.21 mol

Since we started with 1 mol, we need to add 2.21 mol.

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