A 100-kg merry-go-round in the shape of a uniform, solid, horizontal disk of radius 1.50 m is set in motion by wrapping a rope about the rim of the disk and pulling on the rope. What constant force would have to be exerted on the rope to bring the merry-go-round from rest to an angular speed of 0.400 rev/s in 2.00 s

The force required is equal to .

Explanation:

We know that

     Torque = force × perpendicular distance

                  = F × R = I×

               I = M×

  From above equation              .............. 1

      We know that

                                   ...........................2

               Given that t= 2 sec

From equation 1 and 2 , we get

                  F =    =  

    Upon substituting the above values we will be getting

          F =

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