You cool a 120.0 g slug of red-hot iron (temperature 745 ∘C) by dropping it into an insulated cup of negligible mass containing 85.0 g of water at 20.0 ∘C. Assume no heat exchange with the surroundings. What is the final temperature of the water?
What is the final mass of the iron and the remaining water?
Express your answer using three significant figures.

Explanation:

Heat lost by hot slug = gain gained by water

If we take that equilibrium temperature be boiling point is 100°C

Heat gained by water = 85 x 10⁻³ x 4.2 x 10³ x ( 100 - 20 )

= 28560 J

Heat lost by slug

= 120 x 10⁻³ x 460.55 x (745-100)

= 35646.570 J

So some water will be evaporated . Let it be m kg

35646.570 = 28560 + m x 2268 x 10³

m = 3.12 x 10⁻³ kg

= 3.12 g

3.12 g of water will be evaporated .

final mass = 120 + 85 - 3.12

= 201.88 g

= 202 g

explanation: in any substance/object, the particles inside it (atoms/molecules) constantly move in random directions and with random speeds (this motion is called brownian motion). as a result, the particles have some kinetic energy (which is proportional to the temperature of the substance).

explanation:

have a great day!

probably not the "magnets"in the magnet, so to speak, are thought to be electrons orbiting in shells. vurrent loops two sides to the loop