A 5.80kΩ5.80kΩ resistor in a circuit has two mesh currents flowing through it. The first current measures 3.10mA3.10mA. The second current, flowing through the resistor in the opposite direction, measures 1.10mA1.10mA. What is the power dissipated by the resistor?

power = 23.2 mW

Explanation:

given data

resister r = 5.80 kΩ

current measures I1 =  3.10 m A

measure current I2 = 1.10mA

solution

we get here I total

I = current 1 - current 2

I = 3.10 - 1.10

I = 2 mA

so here power will be

power = I²×R    1

power = 2² ×  5.80

power = 23.2 mW

laticia draws the diagram below to show earth’s magnetic field.

answer

the arrows to the right of earth should point up.

the answer is ampere

the ampere is used to measure electricity. an ampere is a unit of electric current equal. a unit of measure for the flow of current in a circuit. one ampere is the amount of current flow provided when one volt of electrical pressure is applied against one ohm of resistance.