For the reaction fe3o4(s) + 4h2(g) --> 3fe(s) + 4h2o(g)

h° = 151.2 kj and s° = 169.4 j/k

the equilibrium constant for this reaction at 328.0 k is

Answer : The value of equilibrium constant for this reaction at 328.0 K is

Explanation :

As we know that,

where,

= standard Gibbs free energy  = ?

= standard enthalpy = 151.2 kJ = 151200 J

= standard entropy = 169.4 J/K

T = temperature of reaction = 328.0 K

Now put all the given values in the above formula, we get:

The relation between the equilibrium constant and standard Gibbs free energy is:

where,

= standard Gibbs free energy  = 95636.8 J

R = gas constant  = 8.314 J/K.mol

T = temperature  = 328.0 K

K = equilibrium constant = ?

Now put all the given values in the above formula, we get:

Therefore, the value of equilibrium constant for this reaction at 328.0 K is

the old alchemists made significant contributions to science even though there starting premises were off a bit. their conclusions after failure would steer them into better directions for investigation. science is no more than close observation and the initial mistakes result in rethinking and retrying experiments.

it is a good conductor

explanation: