A gymnast of mass 67.0 kg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume that the rope does not stretch. Use the value 9.81m/s2 for the acceleration of gravity.

Calculate in Newtons:

a. The tension T in the rope if the gymnast hangs motionless on the rope.
b. The tension T in the rope if the gymnast climbs the rope at a constant rate.

Explanation:

Given that,

Mass of the gymnast, m = 67 kg

Acceleration due to gravity,

(a) We need to find the tension T in the rope if the gymnast hangs motionless on the rope. In this case, the tension in the rope is equal to its weight. So,

(b) In this case, we need to find the tension T in the rope if the gymnast climbs the rope at a constant rate. So, the value of acceleration, a = 0. So,

Hence, this is the required solution.

f=ma newton's second law 7x8=56n

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer