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Option D:

The solution to the system of equations is (8, –12).

Solution:

Given system of equations are

– – – – (1)

– – – – (2)

Lets simplify these equations.

In equation (1), take LCM of the denominator and make the same.

Do cross multiplication, we get

Add 2y on both sides of the equations.

– – – – (3)

In equation (1), take LCM of the denominator and make the same.

Do cross multiplication, we get

– – – – (4)

Substitute equation (3) in (4), we get

Subtract 64 from both sides of the equation.

Divide by –7 on both sides of the equation.

y = –12

Substitute y = –12 in equation (3).

x = 8

The solution to the system of equations is (8, –12).

Hence option D is the correct answer.

Option 4: (8,-12)

Step-by-step explanation:

¼x - ½y = 8

x - 2y = 32

x = 32 + 2y

½x + ¾ = -5

2x + 3y = -20

2(32 + 2y) + 3y = -20

64 + 4y + 3y = -20

7y = -84

y = -12

x = 32 + 2(-12)

x = 8

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation: