A sample of gold has a volume of 2 cm3 and a mass of 38.6 grams. What would be the density, and three other properties of the sample that would be considered physical properties.

The density of the gold is calculated to be "19,300 kg/m³".

Explanation:

Given:

Volume = 2cm³

Mass = 38.6 grams.

To Find:

Density of the gold = ?

Solution:

Density is obtained by dividing mass of the sample by its volume and it is given in the units of kg/m³.

Mass in grams is converted into kg as,

1 g = 0.001 kg

38. 6 g =

Now we have to convert cm³ to m³ as,

1 cm³ = 10⁻⁶ m³

2 cm³ = 2 × 10⁻⁶ m³

So Density =

Physical properties of Gold:

i don't know, you need to give me some answers.

explanation:

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

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