Aboat moves through the water with two forces acting on it. one is a 2.96×103 n forward push by the motor, and the other is a 1.86×103 n resistive force due to the water. what is the acceleration of the 1117 kg boat? answer in units of m/s 2 .

if it starts from rest, how far will it move in
17.9 s?
answer in units of m.

what will be its speed at the end of this time
interval?
answer in units of m/s

(a)

(b) 157.76679 m

(c) 17.62757 m/s

Explanation:

Net force acting,

Acceleration, where m is the mass

(b)

From kinematic equation

where s is displacement, u is initial velocity, t is time taken and a is acceleration.

Considering that u=0 since it starts at rest

and substituting the value of a as calculated in part a, t is 17.9 s hence

(c )

From kinematic equation

v=u+at where u and v are initial and final velocities respectively, a is acceleration and t is duration in seconds. Since it starts from rest, u=0 and substituting the value of a as found in part a, t given as 17.9 s we get

V=0+0.984781*17.9=17.62757 m/s

u=13

v=30

s/t=u+1\2at

=13+431/2

=13+265.5

=278.5

spare some change and give it to the poor

explanation:

plz : ((