A stunt car starts at rest at a distance 85m from the edge of a 250m tall cliff. The car accelerates 9 m s toward the / 2 edge of the cliff. As the car leaves the cliff, it falls into the water below. How long did it take to hit the ground?

7.14 s

Explanation:

The motion of the car is a projectile motion, which consists of two independent motions:

- A uniform motion along the horizontal direction (constant velocity)

- A uniformly accelerated motion along the vertical direction (free fall)

To find the time of flight of the car, we just analyze the vertical motion, using the suvat equation:

where:

s = 250 m is the vertical displacement, which is equivalent to the height of the cliff (we take the downward direction as positive direction)

u = 0 is the initial vertical velocity of the car

is the acceleration due to gravity

t is the time of flight

And solving for t, we find:

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the total distance traveled by the car is

30km + 49km = 79 km .