What is the change in the gravitational potential energy of the system of blocks and Earth when the 3.7-kg block has dropped 0.48 m ?

The PE of system changed from 17.40 joules to 0 joules

Explanation:

Here m= mass of block = 3.7 kg

g= gravitational acceleration = 9.8 m/sec2

h= Height = 0.48 m

Potential energy at point A

PE= mgh = 3.7 × 9.8 × 0.48= 17.40 j

At point B 0.48 m below on ground

PE = mgh =3.7 × 9.8 × 0 = 0

96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.