The gravitational force between two 0.800 kg balls is 8.92 x 10-11 N. How far apart are they?

The distance apart between the two balls is 0.69 m

From the question given above, the following data were obtained:

Mass of 1st ball (M₁) = 0.8 Kg

Mass of 2nd ball (M₂) = 0.8 Kg

Force (F) = 8.92×10¯¹¹ N

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

The distance apart between the two balls can be obtained as follow:

Thus, the distance apart is 0.69 m.

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r = 0.692m

Explanation:

According to law of gravitation, the force of attraction F existing between two masses m1 and m2 is directly proportional to the product of the masses and inversely proportional to the square of the distance (r) between them.

Mathematically, F= Gm1m2/r² where G is the gravitational constant.

Given F = 8.92 x 10^-11 N

m1 = m2 = 0.8kg

G = 6.67×10^-11 m³/kgs²

r = ?

Substituting this values in the given formula, we have;

8.92×10^-11 = 6.67×10^-11(0.8)(0.8)/r²

Cross multiplying;

8.92×10^-11r² = 4.27×10^-11

r² = 4.27×10^-11/8.92×10^-11

r² = 0.479×10^0

r² = 0.479

r = √0.479

r = 0.692m

This shows that the masses are 0.692m apart.

explanation:

v=uf/(u-f)

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pe = weightxheight = 2000x1000=2,000,000joules