You're stuck in the exit row on a long flight, and you suddenly worry that your seatmate, who is next to the window, might pull the emergency window inward while you're in flight. the window measures 50 cm by 90 cm. cabin pressure is 0.75 atm, and atmospheric pressure at the planes altitude is 0.25 atm. should you worry?

You should not worry since the force required is F = 22798 N ( equivalent to being able to lift a mass of 2326 Kg)

Explanation:

Since the pressure of the cabin is higher than pressure inside the plain, then there is a net force exerted by the air outwards , that your seatmate should overcome if he tries to pull the emergency window inwards.

This force is equal to

F = ΔP*A

where

F= force required

P = pressure difference

A= area of the window=

replacing values , and since 1 atm = 101325 Pa and 1 m= 100 cm,

F = ΔP*A = (0.75 atm - 0.25 atm) * (50 cm*90 cm) * 101325 Pa/ atm * 1 m/100 cm* 1 m/100 cm = 22798 N

F = 22798 N

to put it in more visual terms, that would be equivalent to being able to lift a mass of

m =F/g = 22798 N/(9.8 m/s²) = 2326 Kg

Side note:

Even though is not possible to open the window, windows are the easier to open than cabin doors ( https://www.bbc.com/mundo/noticias-50809246 )

hi there!

out of the two, (b) precision would be more reasonable.   however, both a and b could be pretty reasonable.

-awesomerepublic   : )

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