Abaseball (m = 145 g) approaches a bat horizontally at a speed of 36.0 m/s (80.5 mi/h) and is hit straight back at a speed of 47.8 m/s (107 mi/h). if the ball is in contact with the bat for a time of 1.10 ms, what is the average force exerted on the ball by the bat? neglect the weight of the bat, since it is so much less than the force of the bat. choose the direction of the incoming ball as the positive direction.

F = 11046 N

Explanation:

given,

mass of the baseball (m)= 145 g = 0.145 Kg

horizontal speed(u) = -36 m/s

ball hit is straight back(v) = 47.8 m/s

time of contact = ?

using formula of impulse

Impulse = change in momentum

I = m v - m u

I = 0.145 x (47.8 - (-36))

I = 0.145 x (83.8)

I = 12.151 kg.m/s

we also know

I = F x t

now,

F x t = 12.151 kg.m/s

F x 1.1 ms = 12.151

F = 11046 N

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.

the force represented by vector a is normal force. if the hockey puck is moving to the right, when it is hit with a significant force by the hockey stick the puck will move off in a different direction. correct on edge.