Abiologists have studied the running ability of the northern quoll, a marsupial indigenous to australia in one set of experiments, they studied the maximum speed that quolls could run around a curved path without slipping. one quoll was running at 2.4 m/s around a curve with a radius of 1.6 m when it started to slip.
what was the coefficient of static friction between the quoll's feet and the ground in this trial?

Coefficient of static friction = 0.37

Explanation:

At the point the the quoll slides, quoll attains its maximum velocity.

So Ne = (mv^2)/r equa 1

And N =mgequ 2

Where N vertical force of qoull acting on the surface, e = coefficient of friction, m=mass, g=9.8m/s^2, r =radius =1.6m, v= max velocity of quill = 2.4m/s

Sub equ 2 into equ 1

Mge= (mv^2)/r ...equa3

Simplfy equ3

e = v^2/(gr)...equ 4

Sub figures above

e = 5.76/(9.8*1.6)

e = 0.37

less than one you can't create energy

see earlier answer