A77.4-g sample of an alloy at 93.0°c is placed into 271 g of water at 22.0°c in an insulated coffee cup. assume that no heat is absorbed by the cup. if the final temperature of the system is 31.1°c, what is the specific heat capacity of the alloy in j/(g. k)? don't include units.

the specific heat capacity of the alloy in J/(g.K) is

Explanation:

Knowns

Final temperature , mass of water , specific heat capacity of water , initial temperature of water , mass of the alloy and initial temperature of the alloy .

Applying Formula

We are going to use the following formula

Finally in this case, as the specific heat capacity is measured grade per grade, conversion between Celsius and Kelvin is direct 1:1

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow

probably not if net force is zero