A60-kilogram man holding a 20-kilogram box rides on a skateboard at a speed of positive 7 meters per second. he throws the box behind him, giving it a velocity of negative 5 meters per second, with respect to the ground. what is his velocity, in meters per second, after throwing the object?

Explanation:

It is given that,

Mass of the man, m₁ = 60 kg

Mass of the box, m₂ = 20 kg

Speed of man+ box, V = +7 m/s

Speed of the box, when it was thrown, v₂ = -5 m/s

To find,

Velocity of the man after throwing the box

Solution,

Let v₁ be the velocity of the man after throwing the box. By using the conservation of momentum, it can be calculated.

Therefore, the velocity of the man after throwing the object is 11 m/s towards his initial direction.

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