To assess whether your calculations make sense, let's simplify the problem even further and assume air resistance is negligible. in this case, the net force acting on the bicyclist is equivalent to just the force of static friction, and your answer to part d is the magnitude fs. based on this value, what is the minimum coefficient of static friction μs between the race track and the bicycle? express your answer numerically to two significant figures.

Would like to . could you translate to english

490 n  f=125n a=2.5m/s2

Answerthe energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.explanationwe define electric potential as the ratio electric potential energy to the charge,    then the following gives us the potential difference,      the formula  may be on your formula sheet.the change in electric potential energy would be the energy that would needed to move it from point a to point b. solving for that, we get    using q = 8.00  × 10⁻¹⁹ c and  δv = 2.00 v, we get    the energy required is 1.60 × 10⁻¹⁸ j, to three significant figures.