Apoint charge of -3.00 μc is located in the center of a spherical cavity of radius 6.90 cm inside an insulating spherical charged solid. the charge density in the solid is 7.35 × 10−4 c/m3.part acalculate the magnitude of the electric field inside the solid at a distance of 9.20 cm from the center of the cavity. express your answer with the appropriate units. ee=

Electric field will be                        

Explanation:

We have given that a charge of is inside the cavity of sphere

Charge density of sphere

Radius of cavity = 6.90 cm = 0.069 m

We have to find the electric field at 9.20 cm = 0.092 m

So effective radius = 0.092 - 0.069 = 0.023 m

So effective volume

We know that charge = volume × charge density

So charge

So net charge enclosed by sphere

From Gauss law we know that

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