The specific volume of 5 kg of water vapor (h2o) at 1.5 mpa, 440 °c is 0.2160 m/kg. (this could be the condition exiting a boiler in a steam power plant.) we'll learn how to use the "steam tables" to find this information in a couple of weeks.) determine (a) the volume in m, occupied by the water vapor, (b) the amount of water vapor present in gmol and (c) the number of molecules. recall that avagodro's number is na 6.024x1023 molecules/gmol (6.023x 1 026 molecules/kmol). also, the molecular weight of water is very closed to 18.0 g/gmol (kg/kmol). [ans: (a) v 1.08 m] repeat your calculations if the 5 kg of water (h2o) is cooled to a temperature of 40 °c, such that the specific volume is reduced to 0.001007 m/kg. the pressure is still .5 mpa. (this could be the condition entering a boiler in a steam power plant.)