Asky diver, with parachute unopened, falls 625 m in 15.0 s. then she opens her parachute and falls another 362 m in 139 s. what is her average velocity (both magnitude and direction) for the entire fall?
magnitude m/s
so for the free fall v = (a)(t) and because a = g in this instance i did v = (9.8)(15.0) = 147 m/s
so for the free fall velocity = 147
the second part is confusing, the parachute is open so a ! = 9.8 because of the wind drag on the chute, does a = 1/2gt^2? cause if it does i think i can figure it out.