Red laser light from a he-ne laser (λ = 632.8 nm) creates a second-order fringe at 53.2° after passing through the grating. what is the wavelength λ of light that creates a first-order fringe at 22.0°?

Explanation:

It is given that,

Wavelength of red laser light,

The second order fringe is formed at an angle of,

For diffraction grating,

, n = 2

The wavelength λ of light that creates a first-order fringe at 22 is given by :

Hence, this is the required solution.

answerscientific theory;

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j