A2.55-m-long rod, as measured in its rest frame, speeds by you longitudinally at 6.11ã10^7. you measure its length as it passes. by how many millimeters do you determine the rod has contracted?

The length contracts by 54 mm.

Explanation:

According to theory of special relativity the contraction in the length of an object travelling at a speed 'v' is given by

where

L = contracted length of the object

= original length of object

v = speed of the object

c = speed of light

Applying values we get

Thus the change in length equals

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j