An object has a half-life of 3400 years. the initial amount is 24g. how long until 1 gram remain?

1.56 x 10^4 years

Explanation:

Half life, T = 3400 years

initial amount, No = 24 g

Amount remaining, N = 1 g

Let λ be the decay constant.

λ = 0.6931 / T = 0.6931 / 3400 = 2.039 x 10^-4 per year

Let the 1 g amount is remaining in time t.

Take log on natural base on both the sides

t = 1.56 x 10^4 years

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