Find the equivalent capacitance of five capacitors each having 15.0 μf and connected: (a) all in series; (b) all in parallel.

(a) 3.0 μF

(b) 75.0 μF

Explanation:

The equivalent capacitance when the capacitors are connected all in series is:

Where   is the equivalent capacitance, , , , and are the capacitance of each capacitors. In this case, they all have 15.0 μF. So we can replace as:

The solve for :

=3.0 μF

The equivalent capacitance when the capacitors are connected all in parallel is:

Replacing values we get:

=15.0 μF+15.0 μF+15.0 μF+15.0 μF+15.0 μF

=75.0 μF

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