If a planet in our solar system had an 11.2-day orbit, kepler’s third law would say it is about 0.1 au from the sun. proxima is less massive than the sun, so an 11.2-day planet would be closer in than 0.1 au, according to the modified version of kepler’s third law. (with less mass at the center, a 0.1-au planet wouldn’t have to travel as fast in its orbit to “outrun” the star’s gravity.)
let’s figure out just how far away this planet would be from its star. this planet is not going around the sun, so we’ll need to use the extra correction factor in kepler’s third law.

in this image, you can see solar radiation going through ocean water.

no image, but probably absorption

report!

explanation:

physics means: "the branch of science concerned with the nature and properties of matter and energy. the subject matter of physics, distinguished from that of chemistry and biology, includes mechanics, heat, light and other radiation, sound, electricity, magnetism, and the structure of atoms."

get the total number of pieces of fruit and divide it by 4 to get the average. the result is the answer to the problem. 14 total number of fruits and there are 4 members. 14 divided by 4 is equals to 3.5.

t = 1/400 h   ⇔ 0.0025 h ⇔ 9s ⇔ 0.15 m

any of the answers are correct.