In a young's double-slit experiment the wavelength of light used is 466 nm (in vacuum), and the separation between the slits is 1.3 × 10^-6 m. determine the angle that locates: (a) the dark fringe for which m = 0 (b) the bright fringe for which m = 1 (c) the dark fringe for which m = 1 and (d) the bright fringe for which m = 2.

Part a)

Part b)

Part c)

Part d)

Explanation:

For the position of dark fringe the path difference of light is odd multiple of half of the wavelength

so here we will have

part a)

for m = 0 we have

Part b)

Similarly for the maximum intensity we will have path difference must be integral multiple of wavelength

so we have

for m = 1 we have

Part c)

for m = 1 we have

Part d)

for m = 2 again we have