Atank contains 8000 liters of water. each day, half of the water in the tank is removed. how much water will be in the tank at the end of:
a. the 4th day?
b. the 8th day?

On first day the tank had 8000 liters of water.

Half is removed so half of 8000 is 4000.

Subtracting 8000-4000 =4000

So at the end of first day 4000 liters of water is there.

Water in the tank at the end of second day:

Again half of 4000 is removed.

half of 4000 is 2000.

subtracting 4000-2000 =2000.

At the end of second day 2000 l of water is present in tank.

At the end of third day:

Again half of 2000 is removed.

half of 2000 is 1000.

subtracting 2000-1000 =1000.

At the end of third day 1000 l of water is present in tank.

At the end of fourth day:

Again half of 1000 is removed.

half of 1000 is 500.

subtracting 1000-500 =500.

At the end of fourth day 500 l of water is present in tank.

At the end of fifth day:

Again half of 500 is removed.

half of 500 is 250.

subtracting 500-250=250.

At the end of fifth day 250 l of water is present in tank.

At the end of sixth day:

Again half of 250 is removed.

half of 250 is 125.

subtracting 250 - 125 =125.

At the end of sixth day 125 l of water is present in tank.

At the end of seventh day:

Again half of 125 is removed.

half of 125 is 62.5.

subtracting 125-62.5 =62.5.

At the end of seventh day 62.5 l of water is present in tank.

At the end of eighth day:

Again half of 62.5 is removed.

half of 62.5 is 31.25

subtracting 62.5 - 31.25 =31.25.

At the end of eighth day 31.25 l of water is present in tank.

dilation scale factor 2: starting with δabc, draw the dilation image of the triangle with a center at the origin and a scale factor of two. notice that every coordinate of the original triangle has been multiplied by the scale factor (x2). dilation with scale factor 2, multiply by 2.

step-by-step explanation:

is their an equation anywhere i can take a   look at it and see if i am right.