Factor 6a^3-3a^2+8a-4 by grouping the answers are a. (2a-1) (3a^2+4) b. (2a+4) (3a^2-1) c. (6a^3-3a^2) (8a-4) d. cannot be factored i dotn know how to do it

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

the answer is su.k.my? ? co.kc