Arocket is launched at the rate of 11 feet per second from a point on the ground 15 feet from an observer. to 2 decimal places in radians per second, find the rate of change of the angle of elevation when the rocket is 30 feet above the ground.

0.15 rad/s

Step-by-step explanation:

A rocket is launched at the rate of 11 feet per second from a point on the ground 15 feet from an observer.

To find rate of change of angle when the rocket is 30 feet above the ground

Height of rocket, y = 30 feet

Speed of rocket,

Distance of observer from rocket, d = 15 feet

Angle between observer and rocket at height 30 feet is Ф

Distance between observer and rocket launch doesn't change.

So, d=15 will remain constant.

differentiate w.r.t t

Hence, The rate of change of the angle of elevation is 0.15 rad/s

answer: you need to organize this better it does not make sense.

step-by-step explanation: ?

i don't know, but that looks pretty bad. my school passed us unless we failed in all the subjects, but idk abt ur school's rules.

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