Mathematics, 08.07.2019 05:20 erikloza12pdidtx
Find the equation of the line perpendicular to x−5y=15 that passes through the point (−2,5).
Answers: 2
![\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ -2}}\quad ,&{{ 5}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies -5 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-5=-5[x-(-2)] \\\\\\ y-5=-5(x+2)\implies y-5=-5x-10\implies y=-5x-5](/tpl/images/0064/4207/d22bd.png)
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Find the equation of the line perpendicular to x−5y=15 that passes through the point (−2,5)....
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