Will mark match each function to its domain.

f(x) = sqrt(x-5) Domain: all real numbers greater or equal to 5 f(x) = 7/(x-8) Domain: all real numbers except 8 f(x) = sqrt(x) Domain: all positive real numbers and 0 f(x) = 8x Domain: all real numbers The domain of a function is the set of all numbers for which that function is valid. You have 4 functions and 4 possible domains to choose from. Let's work each one out. f(x) = sqrt(x-5) You're not allowed to take the square root of a negative number. So the domain for this function would be all values of x >= 5. That way you're taking the square root of 0 or higher. Let's see if any of your choices match that. And you have the choice "all real number greater or equal to 5" f(x) = 7/(x-8) You're not allowed to divide by 0. And the denomerator becomes 0 if x equals 8. So the domain is all real numbers except 8 which happens to be one of the choices. f(x) = sqrt(x) This is much like the 1st choice. You can't take the square root of a negative number. So the domain is all non-negative numbers. Looking at the choices, there isn't a match, but there's the choice "all positive real numbers and 0" which means the same thing. So that's the answer. f(x) = 8x I don't see anything that would make it impossible to evaluate this expression. So its' domain is all real numbers. And you have that as a choice.

Answer to your question: a. the fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. the roots are ​ x=1±i7√2 .number of roots=degree of polynomialhere, degree of polynomial is 2 so number of roots will be 2.hope it *_*

Ya i could just need to know what type of math