Why is the equation 2+2=4

Well, this is a simple equation when you look at it. Obviously, the answer is Zero. No matter how you rearrange the equation, the answer shoud always be Zero

initial equation: 2+2–4?

Altered equations:

-4+2+2?

2–4+2?

it is always the same. If i were to draw a number line, every time you add two; move two to the right, everytime i subtract four; move 4 to the left. Try it, the answer will always be Zero.

There are also acronyms: BODMAS, BIDMAS, PEDMAS Et Cetera.

these are the order(s) of operations. Search it up. If one ever comes across an equation where all operations are equivalent then solve it from left to right.

Step-by-step explanation:

The answer is 0. Why? Because of the commutative property that basically says no matter what order the numbers are in you'll always yield the same answer. (3+2=5 and 2+3=5)

In this case, 2+2-4=0 because (2+2)=4 , and 4-4=0 because 4 and -4 are additive inverses.

2+2-4=0

4-4=0

0=0

Or

2+2-4=0

2+(-2)=0

2-2=0

0=0

Mark Brainliest!

Step-by-step explanation:

Well, this is a simple equation when you look at it. Obviously, the answer is Zero. No matter how you rearrange the equation, the answer shoud always be Zero

initial equation: 2+2–4?

Altered equations:

-4+2+2?

2–4+2?

it is always the same. If i were to draw a number line, every time you add two; move two to the right, everytime i subtract four; move 4 to the left. Try it, the answer will always be Zero.

There are also acronyms: BODMAS, BIDMAS, PEDMAS Et Cetera.

these are the order(s) of operations. Search it up. If one ever comes across an equation where all operations are equivalent then solve it from left to right.

Step-by-step explanation:

The answer is 0. Why? Because of the commutative property that basically says no matter what order the numbers are in you'll always yield the same answer. (3+2=5 and 2+3=5)

In this case, 2+2-4=0 because (2+2)=4 , and 4-4=0 because 4 and -4 are additive inverses.

2+2-4=0

4-4=0

0=0

Or

2+2-4=0

2+(-2)=0

2-2=0

0=0

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations: