Can someone please help me with this square root problem?

c = 14.9

Step-by-step explanation:

use the pythagorean thereom:

a² + b² = c²

a² = 11 × 11 = 121

b² = 10 × 10 = 100

c² = 121 + 100 = 221

now find the square root of 221:

√221 = 14.866...

round to the nearest tenth:

the 6 next to the 8 means round up.

so the hypotenuse is 14.9

arithmetic sequence

step-by-step explanation:

given that a sequence has terms as

19, 15, 11,

this is represented on a graph

the pattern indicates that the sequence is an arithmetic sequence with i term

a=19 and common difference d =-4

any general term

thus the sequence is reduced by 4 for each successive term starting from 1 and nth term is

24-5n.

first negative term would start after 5th term

5th term =24-25< 0

from 5th term onwards the sequence would be negative.

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4